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Jeanmar Gomez Hopes To Give Indians 2 Straight Over Oakland Tuesday Night

Jeanmar Gomez gets the call tonight for the Indians as they try to make it two wins in a row over the visiting Oakland Athletics.

Gomez, recalled from Columbus to make a start in the rotation-spot vacated by the disabled Josh Tomlin, will be making his sixth appearance of the year for the Tribe, but his first since July 17 and only his second since May 5. Gomez (0-2) lost in his last start when he went 5.1 innings and allowed five runs in an 8-3 loss to the Orioles in Baltimore.

Jeanmar faced the Athletics in Oakland on May 5, getting no decision in a game won by the Tribe 4-3. Gomez went 5.1 frames that day, allowing six hits but only one run in the only outing vs. Oakland in his career.

The Athletics will send Trevor Cahill (9-12, 4.13 ERA) against the Tribe tonight. Cahill was the winning pitcher in a 3-1 A’s win on May 4, a game in which Cahill surrendered only one run on five hits in seven innings, to run his career mark vs. Cleveland to 2-1 in 17.2 innings over three starts.

Cahill has had his problems away from the spacious Oakland Coliseum in 2011, going 4-5 away from home in 14 starts, and with a 5.24 ERA.

The Indians remained in third place in the AL Central after their victory last night when the second-place White Sox also won, but both teams gained a game on the division-leading Tigers, who lost at home to the Royals.

This series will continue on Wednesday night when Ubaldo Jimenez takes on Oakland’s Rich Harden.

Photographs by spatulated, Triple Tri, and chrischappelear used in background montage under Creative Commons. Thank you.